SET A
1. Write a program to accept an integer and check if it is even or odd.
#include<stdio.h>
#include<conio.h>
void main()
{
int no;
clrscr();
printf("\nFinding giving no is even or odd:");
printf("\nEnter the number:");
scanf("%d",&no);
if(no%2==0)
printf("\n%d NO is even:",no);
else
printf("\n%d NO is odd:",no);
getch();
}
/*
Finding giving no is even or odd:
Enter the number:4
4 NO is even:
Finding giving no is even or odd:
Enter the number:5
5 NO is odd:
*/
2] Write a program to accept three numbers and check whether the
first is between the other two numbers.
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c,mid,min,max;
clrscr();
printf("\nEnter first no:");
scanf("%d",&a);
printf("\nEnter Second no:");
scanf("%d",&b);
printf("\nEnter third no:");
scanf("%d",&c);
if(a<b&&a>c||a>b&&a<c)
mid=a;
if(b>a&&b<c||b<a&&b>c)
mid=b;
if(c>a&&c<b||c<a&&c>b)
mid=c;
printf("\nMid:%d",mid);
getch();
}
/*
Enter first no:20
Enter Second no:10
Enter third no:30
Mid:20
*/
3]Accept a charcter as input and check whether the character
is digit.
#include<stdio.h>
#include<conio.h>
void main()
{
char ch;
clrscr();
printf("\nEnter the charcter:");
scanf("%c",&ch);
if(ch>='0' && ch<='9')
printf("\n character is a digit between 0 to 9 charcters:");
else
printf("\n character is not a digit between 0 to 9:");
getch();
}
/*
Enter the charcter:4
character is a digit between 0 to 9 charcters:
Enter the charcter:A
character is not a digit between 0 to 9:
*/
4]Write a program to accept a number and check if it is
divisible by 5 and 7.
#include<stdio.h>
#include<conio.h>
void main()
{
int no;
clrscr();
printf("\nEnter the no:");
scanf("%d",&no);
if((no%5==0)&&(no%7==0))
printf("\n%d is divisible by 5 and 7:",no);
else
printf("\n%d is not divisible by 5 and 7:",no);
getch();
}
/*
Enter the no:35
35 is divisible by 5 and 7:
Enter the no:55
55 is not divisible by 5 and 7:
*/
5] Write a program,which accepts annual basic salary of an employee and calculates
and display the income tax as per the following rules.
Basic:<1,50,000 Tax=0
1,50,000 to 3,00,000 tax=20%
>300000 tax=30%
#include<stdio.h>
#include<conio.h>
void main()
{
float tax=0,as,limit;
clrscr();
printf("\nEnter the Annual salary of emp: ");
scanf("%f",&as);
limit=150000;
if(as<=limit)
printf("\nfor %f NO Tax: ",as);
else if(as>150000&&as<300000)
tax=(as-limit*0.1)*0.1;
else if(as>300000)
tax=(as-limit*0.1)*0.3;
printf("\nOn salary: %f Tax is:%f",as,tax);
getch();
}
/*
Enter the Annual salary of emp: 7000
for 7000.000000 NO Tax:
On salary: 7000.000000 Tax is:0.000000
Enter the Annual salary of emp: 200000
On salary: 200000.000000 Tax is:18500.000000
Enter the Annual salary of emp: 500000
On salary: 500000.000000 Tax is:145500.000000
*/
6 ] Accept a lowercase character from the user and check whether
the character is a vowel or consonant.
#include<stdio.h>
#include<conio.h>
void main()
{
char c;
clrscr();
printf("\nEnter the lowercase character:");
scanf("%c",&c);
if(c=='a'||c=='e'||c=='i'||c=='o'||c=='u')
printf("\n%c charcter is vowel:",c);
else
printf("\n%c not vowel:",c);
getch();
}
/*
Enter the lowercase character:E
E charcter is vowel:
Enter the lowercase character:e
e charcter is vowel:
Enter the lowercase character:d
d not vowel:
*/
SET B
1]Write a program to check whether gien character is a digit or character in
lowecase or uppercase alphabet.
#include<stdio.h>
#include<conio.h>
void main()
{
char c;
int ch;
clrscr();
printf("\nEnetr the charcter:");
scanf("%c",&c);
ch=c;
if(ch>=48&&ch<=58)
printf("\n%c Character is digit:",c);
else if(ch>=97&&ch<=122)
printf("\n%c Charcter is lowercase Alphabet:",c);
else
printf("\n%c Charcter is uppercase Alphabet:",c);
getch();
}
/*
Enetr the charcter:A
A Charcter is uppercase Alphabet:
Enetr the charcter:a
a Charcter is lowercase Alphabet:
Enetr the charcter:4
4 Character is digit:
Enetr the charcter:+
Special character:
*/
2]Accept the time as hour,minute and second and check whether the
time is valid.
#include<stdio.h>
#include<conio.h>
void main()
{
int h,m,s;
clrscr();
printf("\nEnter the time");
printf("\nEnter hours:");
scanf("%d",&h);
printf("\nEnter minute:");
scanf("%d",&m);
printf("\nEnter second:");
scanf("%d",&s);
if(h<=24&&m<=60&&s<=60)
printf("\nTime is valid:");
else
printf("\nTime is not valid:");
getch();
}
/*
Enter the time
Enter hours:22
Enter minute:55
Enter second:33
Time is valid
Enter the time
Enter hours:26
Enter minute:33
Enter second:33
hours is invalid:
Enter the time
Enter hours:22
Enter minute:61
Enter second:33
Minute is invalid:
*/
3]Accept any year as input through the keyboard.write a program
to check whether the year is a leap year or not.
#include<stdio.h>
#include<conio.h>
void main()
{
int yr;
clrscr();
printf("\nEnter the year:");
scanf("%d",&yr);
if(yr%4==0 && !(yr%100==0))
printf("\n%d year is leap year :",yr);
else
printf("\n%d year is not leap year:",yr);
getch();
}
/*
Enter the year:2017
2017 year is not leap year:
Enter the year:2018
2018 year is not leap year:
Enter the year:2019
2019 year is not leap year:
Enter the year:2020
2020 year is leap year :
*/
4] Accept three sides of triangle as input,and print whether
the triangle is valid or not.(hint:the triangle id valid if the sum
of each of the two sides is greater than the third side )
#include<stdio.h>
#include<conio.h>
void main()
{
int a,b,c;
clrscr();
printf("\nEnter the sides of ABC triangle:");
printf("\nEnter the AB lenght in cm:");
scanf("%d",&a);
printf("\nEnter the BC lenght in cm:");
scanf("%d",&b);
printf("\nEnter the Ac lenght in cm:");
scanf("%d",&c);
if((a+b)>c)
printf("\nABC is valid triangle:");
else
printf("\nABC is not valid triangle:");
getch();
}
/*
Enter the sides of ABC triangle:
Enter the AB lenght in cm:3
Enter the BC lenght in cm:5
Enter the Ac lenght in cm:6
ABC is valid triangle:
Enter the sides of ABC triangle:
Enter the AB lenght in cm:0
Enter the BC lenght in cm:-2
Enter the Ac lenght in cm:
5
ABC is not valid triangle:
*/
5] Accept the X and Y co-ordinate of a point and find
the quadrant in which the point lies.
#include<stdio.h>
#include<conio.h>
void main()
{
int x1,y1,x2,y2;
clrscr();
printf("\nEnter Point A co-ordinate:");
printf("\nEnter X co-ordinate:");
scanf("%d",&x1);
printf("\nEnter Y co-ordinate:");
scanf("%d",&y1);
printf("\nEnter Point B co-ordinate:");
printf("\nEnter X co-ordinate:");
scanf("%d",&x2);
printf("\nEnter the y co-ordinate:");
scanf("%d",&y2);
getch();
}
/*
Enter Point A co-ordinate:
Enter X co-ordinate:1
Enter Y co-ordinate:2
Quadrant I:
Enter Point A co-ordinate:
Enter X co-ordinate:-1
Enter Y co-ordinate:2
Quadrant II:
Enter Point A co-ordinate:
Enter X co-ordinate:-1
Enter Y co-ordinate:-4
First Quadrant: III
Enter Point A co-ordinate:
Enter X co-ordinate:4
Enter Y co-ordinate:-3
First Quadrant:IV
Enter Point A co-ordinate:
Enter X co-ordinate:0
Enter Y co-ordinate:0
Origin:
*/
/*Lab Course:1 Exercise:2 Set:B
Example:6-Write a program to roots of a quadratic equation.
Consider all possible cases.
*/
#include<stdio.h>
#include<conio.h>
#include<math .h>
void main()
{
double r1,r2,a,b,c,dm,img,realpart;
// clrscr();
printf("\nEnter the cofficent a,b,c:");
scanf("%lf%lf%lf",&a,&b,&c);
dm=b*b-4*a*c;
if(dm>0)
{
r1=-b+sqrt(dm);
r2=-b-sqrt(dm);
printf("\nroot1=%lf\nroot2=%lf",r1,r2);
}
else if(dm==0)
{
r1=r2=-b/2*a;
printf("\nroot1=root2=%lf",r1);
}
else if(dm<0)
{
realpart=-b/2*a;
img=sqrt(-dm)/2*a;
printf("\nroot1=%lf+i%lf\nroot2=%lf-i%lf",realpart,img,realpart,img);
}
getch();
}
/*
Enter the cofficent a,b,c:1
1
1
root1=-0.500000+i0.866025
root2=-0.500000-i0.866025
Enter the cofficent a,b,c:1
4
1
root1=-0.535898
root2=-7.464102
Enter the cofficent a,b,c:1
2
1
root1=root2=-1.000000
*/
Example:7-Accept the cost price and seeling price from the keyboard.
Find out if the seller has made a profit or loss and display
how much profit or loss has been made.
#include<stdio.h>
#include<conio.h>
void main()
{
int cp,sp,x;
// clrscr();
printf("\nEnter Cost prize:");
scanf("%d",&cp);
printf("\nEnter Seeling prize:");
scanf("%d",&sp);
x=sp-cp;
if(x>0)
printf("\nProfit is %d",x);
else
printf("\nLoss is %d",x);
getch();
}
/*
Enter Cost prize:10
Enter Seeling prize:12
Profit is 2
Enter Cost prize:20
Enter Seeling prize:15
Loss is -5
*/
SET C Write programs to solve the following problems
/*
1. Write a program to accept marks for three subjects and find the total marks secured ,
average and also display the class obtained. (Class I – above __%, class II – ___% to ___%,
pass class – ___% to ___% and fail otherwise)
*/
#include<stdio.h>
#include<conio.h>
void main()
{
float m1,m2,m3,total,classs,avg ;
clrscr();
printf("\nEnter 3 subject marks:");
scanf("%f%f%f",&m1,&m2,&m3);
total=m1+m2+m3;
printf("\nTotal marks: %f",total);
avg=total*100/300;
printf("\nAvg : %f%",avg);
if(avg>=70 && avg<=100)
printf("\nFirst Class with distinction.");
else if(avg>=60 &&avg<70)
printf("\n First Class");
else if(avg>=55 && avg<60)
printf(" Higher second class");
else if(avg>=50 &&avg<55)
printf("second class");
else if(avg>=40 && avg<50)
printf("\nPass CLass");
else
printf("\nFail");
getch();
}
/*
Enter 3 subject marks:40
40
40
Total marks: 120.000000
Avg : 40.000000%
Pass CLass
Enter 3 subject marks:55
55
55
Total marks: 165.000000
Avg : 55.000000% Higher second class
Enter 3 subject marks:45
89
50
Total marks: 184.000000
Avg : 61.333332%
First Class
*/
